What is the solution set of the quadratic inequality 4(x+2)^2<0

Answer:The solution of the given quadratic inequality is:                         [tex]x=-2[/tex]Step-by-step explanation:Solution of a inequality is the set of all the possible x value which satisfy the inequality i.e. it is the collection of all the possible value which makes the inequality true.We know that the square of any quantity is always greater than or equal to zero.i.e.[tex](x+2)^2\geq 0[/tex]also,[tex]4(x+2)^2\geq 0[/tex]But we are given a inequality as:[tex]4(x+2)^2\leq 0[/tex]Hence, from (1) and (2) we get:[tex]4(x+2)^2=0[/tex]i.e.[tex]x=-2[/tex]                Hence, the solution is:                          x= -2